<p>If f(x)=x^3-x&2-3x-1 and h(x)=f(x)/g(x), evaluate limit as x->0 for (3h(x) + f(x) - 2g(x))</p>
<p>assuming you know h(x):
h is continuous everywhere except x=-1
limit x-> infinity, h(x) = infinity
lim x-> -1, h(x) = 1/2</p>
<p>please please please help</p>