<p>so any one care to give some input.
What about FRQ 3</p>
<p>That one was easy.
Just do taylor polynomials, plug in 1.9
For the last part, use the next term, which is 2.7 x 10^-4, which is smaller than 3 x 10^-4</p>
<p>Wait, how did the error term come out to 2.7 x 10^-4?</p>
<p>It's the next term after the 3rd (or 4th? can't recall) term. So if your approximation function is a fourth-degree, then it's error will be about 2.7*10^-4 because the terms in the taylor series are always decreasing.</p>
<p>Aaargh, I thought that was only for an alternating Taylor Series...</p>
<p>Can somebody post the actual math for how you get the remainder term?</p>
<p>ya its pretty easy okay so since we were using the third degree taylor, for error we use the 4th degree so it becomes: abs((584/9)/4! x (1.9-2)^4) = 2.7037 x 10 ^-4</p>
<p>Wow...I divided by 5! ...do you think I'll get any points at all for that or is that usually just a one-pointer? (I wrote the formula for the lagrange remainder and then just stupidly plugged in the wrong n+1 ...)</p>
<p>I seriously did that exact math and got the wrong answer... WOW</p>
<p>can anyone explain to me the last part on the last question? 6d?</p>