<p>Day 4 & 5</p>
<ol>
<li><p>Need to find (f + h) when x=1
= f(1) + h(1)
= 7 + 6 = 13</p></li>
<li><p>Need to find (k g) when x=5
= k(5) - g(5)
= ( 5^2 + 5) - sqrt(5-3) [Assuming k(x) = x^2 + 5, not 2x + 5]
= 25 + 5 - 1.414
= 28.586</p></li>
<li><p>(f ◦ h)(3)
= f(3) * h(3)
= (5)(2) = 10</p></li>
<li><p>(g ◦ k)(7)
= sqrt(x-3) * (x^2 + 5) when x=7
= sqrt(4) * (7^2 + 5)
= 2 * (49 + 5) = 108</p></li>
<li><p>f -1(x)
= f(x) - 1
= {(3,4), (2,3), (1,6)}</p></li>
<li><p>k-1(x)
= k(x) - 1
= (x^2 + 5) - 1
= x^2 + 4</p></li>
<li><p>1/f(x)
= {(3,1/5), (2,1/4), (1,1/7)}</p></li>
<li><p>(kg)(x)
= k(x) * g(x)
= (x^2 + 5) * sqrt(x-3)</p></li>
</ol>