<p>I- (aq) + ClO- (aq) --> I3- (aq) + Cl- (Aq)</p>
<ul>
<li>the 3 in I3 is a subscript</li>
</ul>
<p>the answer is 2H+ + 3I- + ClO- --> I3- + Cl- + H20</p>
<p>but I had a 3e- on the reactant side and I don't understand why there ISN'T a 3e- . something is probably wrong with my oxidation numbers but I'm not sure what it is..</p>