<p>Can someone explain why the chapter 9 practice question 24 is not D but E? The explanation is dumb lol</p>
<p>Well, the answer is C, in my PR book (2009) edition, but if its the same question, here’s my explanation:
Try visualizing an increase in pressure. It’s like sitting on something, so an increase in pressure is basically equivalent to a decrease in volume of the container. If you have a smaller volume, then there is less room for the carbon dioxide to avoid the water. Thus, there is a greater chance that the carbon dioxide will react with the water in a smaller container (more collisions). Also, decreasing the temperature just makes the gas more soluble. I don’t know how to explain it as it is a little counterintuitive, but you should just remember that the lower the temperature and the higher the pressure, the more soluble the GAS.</p>
<p>Yea, basically what he said.</p>
<ul>
<li>A gas’s solubility increases as the temperature of the solvent decreases</li>
<li>Think of it like soda. A soda bottle when unopened has no bubbles (CO2) because there’s so much pressure on it. When you decrease the pressure (either by shaking or opening), bubbles form. So therefore to keep the CO2 dissolved, you increase the pressure.</li>
</ul>