<p>Calculate the molar solubility of Co(OH)3, Ksp = 2.5 * 10^ -43</p>
<p>the answer is 2.5*10^-22</p>
<p>But can someone explain how...</p>
<p>Where are you getting that answer from? According to that Ksp, it is not the right answer.</p>
<p>The reaction here is Co(OH)3 --> Co(3+) + 3OH-</p>
<p>If we set moles of cobalt (III) hydroxide equal to "x", then our Ksp equation is:</p>
<p>2.5<em>10^-43 = (x)(3x)^3, or 2.5</em>10^-43 = 27x^4</p>
<p>Solving for "x" we get 9.81*10^-12 mol/L.</p>