<p>COpper Chloride will be least soluble in a 0.02 molar solution of which of he following compounds?</p>
<p>NaCl
CuNO3
CACL2
NACO3</p>
<p>CaCl2, because CuCl can be shown by this reaction:</p>
<p>CuCl(s) –> Cu+1(aq) + Cl-1(aq)</p>
<p>putting it in a solution of CaCl2 adds extra moles of Cl-1 which shifts the reaction the the left. NaCl and CuNO3 also shift it to the left for similar reasons but CaCl2 creates more ions than the other two solutions.</p>
<p>How does that do with LEAST soluable?</p>
<p>Another question, how can we tell that NH3 is a weak base?</p>
<p>CaCl2 creates .04M of Cl-
CuNO3 creates .02M of Cu+
NaCl creates .02M of Cl-</p>
<p>Since adding either ion shifts to the left, you have to choose the molecule that would add the most ions (either Cl- or Cu+) and that is CaCl2</p>
<p>You should know NH3 is a weak base, the best I can tell you is that when you add NH3 to water you get NH4+ and OH- but the creation doesn’t go the full way.</p>
<p>NH3 is just one of those things you need to know.</p>
<p>bestswimmer: is that question from princeton review? I’m pretty sure I saw this question in the study guide because I remember that the answer is CaCl2 because it produces 2 Cl-. I first thought it was CuNO3, but I realize it only produce 1 Cu+.</p>
<p>Yeah, it’s from PR. I totally suck at equilibrium and acids/bases</p>
<p>So why would you ask such a question if PR already explains it to you?</p>
<p>Advice for equilibrium: Have you try doing some practice problems from your textbook? Textbooks provide more specific problems than study guides.</p>