<p>anyone have a good site to learn electrochemistry? still need to review that</p>
<p>does someone know how to balance this using half reaction method in an acidic solution</p>
<p>IO3^- + I^- => I2</p>
<p>Please point out the reduction and oxidation reactions, and the oxidizing and reducing agents THANKS!</p>
<p><a href=“College Board - SAT, AP, College Search and Admission Tools”>College Board - SAT, AP, College Search and Admission Tools;
<p>for question 1a, how come the weak acid dissociates 100%?</p>
<p>@lemone: how else would you write it?</p>
<p>Shouldn’t it be in equilibrium?</p>
<p>Part b is in equilibrium, but part a is just showing wat the weak acid will do in water, which is ionize to a small percentage</p>
<p>@ lemone: i think it’s because they want you to write the equation based on the Ka expression they give you…</p>
<p>But if it dissociates 100%, why would HOCl be at the bottom of the equilibrium expression?</p>
<p>how many other people stayed home from school? haha. just wondering…</p>
<p>Also, how are people feeling about the test? i’m going to act like the mediator for a second…
i actually can’t wait for it. i think i just want to get it over with…</p>
<p>because it’s the Ka expression…
that’s how it’s written?</p>
<p>Kb on the other hand, would have HOCl on the top.</p>
<p>No, but if it dissociates 100%, there shouldn’t be anything on the bottom</p>
<p>it doesn’t say that it disassociates a HUNDRED% though, does it?</p>
<p>Nope, that’s what I am wondering about. It’s a weak acid, so why it disassociates 100%</p>
<p>weak acids don’t disassociate 100% – and that’s why there is HOCl on the bottom.
because it hasn’t disassociated completely…so there is still some (original) HOCl left.</p>
<p>It doesn’t dissociate 100%, the Ka is the degree of dissociation. It is on the bottom because all K equations are products over reactants and it is a reactant.</p>
<p>Heres a nice review question:
26. Of the following organic compounds, which is least soluble in water at 298 K?
(a) CH3OH, methanol
(b) CH3CH2CH2OH, l-propanol
(c) C6H14, hexane
(d) C6H12O6, glucose
(e) CH3COOH, ethanoic (acetic) acid</p>
<p>(c) C6H14, hexane
because c6h14 is the only one without oh-, and molecules that contain oh- are capable of hydrogen bonding, making them capable of hydrogen bonding with water.</p>
<p>^I feel smart because I knew the answer before I scrolled down!</p>
<p>Hehehe. I’m also staying home from school, but I do have a wicked cough. Time to read! X_X</p>
<p>Yup. good job (both of you)</p>
<p>@miheonigirisan</p>
<p>here’s a site i learned electrochem off of LOL
[W</a>. W. Norton & Company | Chemistry 2nd Edition](<a href=“http://www.wwnorton.com/college/chemistry/gilbert2/chemtours.asp]W”>Student | W. W. Norton & Company)
interactive flash 
it was actually pretty helpful though o_O</p>