<p>Yep, you guys got it :)</p>
<p>Let’s try some predicting products questions, since we need to know that for question 4.</p>
<p>Lithium is burned in air.</p>
<p>Carbon disulfide vapor is burned in excess oxygen.</p>
<p>Did anybody do the Fast Track to a 5 review book for AP Chem? Because I have that one and the AP Princeton Review book…but I’m not sure which one is better…</p>
<p>thanks</p>
<p>^ 4Li(s) + O2(g) —> 2Li20(s)???</p>
<p>CS2(s) + O2(g) —> CO2(g) + SO2(s)???</p>
<p>^Both of those sound good.</p>
<p>I don’t get it, so how do we calculator the boiling point then from the boiling-point elevation?</p>
<p>k. got 5’s on PR practice test… is that adequate or is pr A LOT easier than the actual thing</p>
<p>can anybody respond please? did you do Fast Track to a 5 review book for AP Chem and was it helpful?</p>
<p>thanks nonexistent.
Desoan, I’ve heard PR is easier.</p>
<p>delta H > 0 means endothermic or exothermic?</p>
<p>endothermic</p>
<p>Try this question:</p>
<p>All of the following statements concerning benzene, C6H6, are correct EXCEPT
(A) Each carbon atom forms three sigma bonds.
(B) Each carbon is sp2 hybridized.
(C) Pi electrons are delocalized over all 6 carbon atoms.
(D) Benzene forms cis and trans isomers when it reacts.</p>
<p>(A) Because only the first bond is sigma, and all others are pi.</p>
<p>…?
Nope.</p>
<p>Draw it out, each carbon has 3 sigma and 1 pi bond.</p>
<p>D. roflmao at cis and trans isomers for benzene.</p>
<p>are you joking me? cis/trans isomers are on the test??</p>
<p>yea that question seems un-ap like.</p>
<p>I thought that in any compound, the first bond was a sigma bond, and that the others were pi bonds, and how can you tell if a hydrocarbon forms a ring or a chain?</p>
<p>lol dude not in any compound. -_-.</p>
<p>between 2 atoms. the first bond is sigma, all others are pi.</p>
<p>so for benzene. each carbon is connected to 3 other atoms. aka 3 sigma bonds. but it also has a double bond with another carbon. aka a pi bond. and this is for each carbon.</p>
<p>Good job Ilikeyou. I also laughed at the answer choice when I saw it.</p>
<p>@Calculix, pi bonds are only applicable in double or triple bonds.</p>
<p>ohh, I see, thanks for elaborating.</p>