AP Chemistry Help!!!!

<p>The true percentage of sodium carbonate in a smaple of soda ash is 40.24%. A 0.4134 g sample was analyzed by titration with HCl. The sample required 28.56 ml of 0.1106 M HCl for complete neutralization. The equivalent weight of sodium carbonate is 53.00. The relative error, in ppt (parts per thousands would be)</p>

<p>Answer: 6.5</p>

<p>I have no idea; please help!!!!!!!</p>

<p>Ah... how about 6.4?
I didn't know ppt is used as relative error unit on AP Chem
(never learned it so I had to look it up.. pretty much the same idea of % error)</p>

<p>40.24% is Na2CO3, 0.4134g was used.... 0.4024<em>.4134 = true.
Second set of info. 0.02856</em>.1106<em>53.00 = experimental.
per mill error(ppt) = (exp - true)/(true)</em>1000 = 6.377</p>

<p>53.00 can be derived from the balanced equation (which is what I did at first)
I used mass to determine error. mol can also be used to get same answer (more steps)</p>

<p>Oh crap...I am in AP chem and I forgot how to do that...guess it's time to break out the Princeton Review......</p>