<p>We have a test tomorrow and I am so screwed. I still don't understand these equations! If ne one can help w/ 1st order reaction rates w/ the ln part (log base e) it would be greatly appreciated! If not, I'll try to work it out with my text. thanks.</p>
<p>Michele</p>
<p>hey im taking ap chemistry right now, and did the kinetics section a long time ago.</p>
<p>Essentially, kinetics is broken down to zero order, first order and second order.</p>
<p>The part you are talking about is.. im not sure.. but i think the integrated rate law? well the rate law is ln [A] = -kt + ln[A]
[A] is the concentration of the element in question.
-K is the slope of the striaght line or rate constant
t is the time it takes for it to complete the reaction.</p>
<p>the graph for a 1st order is like a -x slope kinda like this L__
\
Its in the 4rth quadrant going from top left to bottom right.</p>
<p>THe formula is basically a plug in one. They will give you.. usually the concentrations of the compound/element. and depending on the problem... like what u need to find.</p>
<p>Some problems are like.. it will give u a set of x (concentration of something0 vs y (time)</p>
<p>and say the directions wanted you to find the rate constant (K)
-plug in, choose one set of x,y for [A] and t.
-then you solve algebraically</p>
<p>If any other problems arise.. or like if any of my explanations didnt make sense.. or it was a different question... feel free to i-m or gimme a message. I'd be glad to help out.</p>
<p>good luck with your test</p>
<p>Thanks for your help! Thats exactly the type of problems we're doing! Thanks for wishing me luck!</p>