<p>Although this problem seems very easy I'm having trouble understanding how to solve it. Any feedback would be greatly appreciated.</p>
<p>A calorimeter has metal parts (heat capacity of 925.0 J C) and 1100 grams of oil (specific heat = 2.824 J G-1 C-1) both at 25.40. Adding a 550 slug, at 220.0 C caused the temperature to rise to 35.2 C. Find the specific heat of the metal.</p>
<p>Just make all the heats transfer equal.
For the oil, 1100g * (35.2-25.4) * 2.814J/gC + (35.2-25.4)*925.0J/C = the sludge =(-1) * 550g * (35.2-220)C * X J/gC
It is negative because there heat would come out to 0 so it could be written as oil + calorimeter + sludge = heat =0</p>
<p>Is the calorimeter suppose to be J/C or is it JC because if its JC then this doesnt work this way.</p>