@helpmeplease2 I thought there wasn’t a curve for AP
isn’t it just set at a certain percentage for a score- like 71% for a 5 and so on?
That’s still a curve. Otherwise a 90 would be a 5, etc.
there were decent amount of rotation problems, but they weren’t hard. springs were more frequent, and some were harder
Okay it looked like gravity pulling on the wheel at the center of mass [at its center] straight downwards, the normal force perpendicular to the surface and emanating from the bottom of the wheel, and the static friction force working against the wheel at its bottom @wormholes
Did anyone else have form E???
I might have I don’t remember for sure. What’s the difference @deeznuts
Completely different questions, including the FRQ. I believe there was a Form O as well
How was the magnitude of the acceleration of the wheel calculated?
Mgsinø-.4mgsinø=ma
Gsinø-.4gsinø=a
.6gsinø=a
Right that’s what I got @Dayruiner
@Dayruiner @ikhan4 do you think they would accept a = (0.6mgsin(theta)) / m? It said in the instructions to use m and theta so i didn’t cancel out the m’s
I mean. It’s equivalent. I know it stated that the variables it can be answered in is M ø and constants but I don’t know if you’re required. I think they set a guideline for acceptable variable to ensure no one attempts to use mu mgcosø to represent frictional force.
How would someone answer part d of FR #3?
D) i. The data is consistent with the student’s equation, because her equation shows that if M increases, Vavg increases. The graph shows this correlation.
ii. Her equation does not make physical sense- you could justify this in several ways. One way: part b of FR#3 shows that when d increases, Vavg increases, but her equation suggests that when d increases, Vavg decreases.
@xybear But doesn’t her data show a slope that is not linear and her equation would create a linear slope
@xybear Thanks. I think I got a four. Thank Gosh!!! 
Also what concept are they trying to get at in question 2 part c?
@lrylander If I had to guess it would be one’s ability to analyze data or something along that line
@lrylander And too I would argue that the line of best fit would be linear.