<p>Yeah, and to pass you only need to get like a third! Wooohhoooo! Still getting a 2. Sad thing is, I got a 5 on Physics C Mechanics. (And would've have scored a 1 on E&M had I taken it.) So what do you think? Is there enough Mechanics on the test for me to pass?</p>
<p>Oh, and another thing. What do you guys prefer, Kaplan or Barron's? I printed all the old free-response, but I don't even know where to start!</p>
<p>And if you guys know any of those freakishly smart, Physics whiz kids, arrange for them to have a little "accident" on the way to the test. Don't let them spoil the curve!</p>
<p>If you had a circuit with a capacitor, no-resistance battery, a few resistors hooked up both in parallel and in series, and a switch, how would you figure out the current through any one of the resistors (i.e. both those in parallel and in series).You know the resistances of each resistor, the voltage of the battery, and the capacitance of the capacitor. I always think V = IR and just add the resistors, but how do you factor in the capacitor?</p>
<p>If this is too confusing, you can take a look at a diagram (<a href="http://www.collegeboard.com/prod_downloads/ap/students/physics/ap_cd_physics.pdf)%5B/url%5D">http://www.collegeboard.com/prod_downloads/ap/students/physics/ap_cd_physics.pdf)</a>. It's a multiple choice test from College Board and the question is #11 under the AP Physics B Sample Multiple Choice heading.</p>
<p>Thanks</p>
<p>I'm using the barrons to review the chapters i don't really know. Good practice if you ask me. I was using my text book, then i remembered i bought the barrons last summer. questions are a lot more AP like, so i'm using that for practice</p>
<p>M17: Number 11's easy... the switch is open, so the capacitor's not even taken into account. Just add up the resistors [4+6+10 = 20ohms] and use V = IR, [12v]=*[20ohms], I = 12/20 = 0.6. Answer: B.</p>
<p>Anyone up for helping me compile a list of formulas we should know? (whether that means memorize or understand how to use) I think it might help, but whatever.</p>
<p>Nah, you're given an equation sheet, just review that.</p>
<p>Yeah i think you'll be alright from the equation sheet. If not, most equations can be made out of combinations of others</p>
<p>Is Kaplan's prep book good enough?</p>
<p>PR is good, but the free response seem very hard for me.</p>
<p>I have a list of every equation to memorize for every chapter from PR typed up in pretty print... but i am too lazy to go down and load em onto my website... oh well. I am using Barrons to prep. So how much for a 5?</p>
<p>why did you mention that? are we supposed to have appreciated that?</p>
<p>what do you need to get a 5?</p>
<p>If a 3 is 1/3 and a 4 is 1/2, then it seems like a 5 would be about 60-65%. But are you guys sure about the 1/3 for a three and 1/2 for a two thing? That doesn't seem right. In PR, they have it at 45% for a 3 and 60% to get a 4. So which is correct? BTW, PR has a 5 at 75%, which would pretty much be one of the highest percentages for a 5 for APs.</p>
<p>If you have a pump at the bottom of a well connected by a pipe to a house at the top of a hill, how would you figure out the work done to pump a specific amount of water to the house at the top of the hill?</p>
<p>in a position vs time graph, if its in negative quadrant, does that mean positive velocity or negative ? how about acceleration</p>
<p>did anyone think the PR practice test hard?</p>
<p>I haven't taken it yet, but if it's anything like the practice questions at the end of the chapter, well, I only got 5 of 10 right...on chapter 2...weeps.</p>
<p>Yeah so I'm screwed basically.</p>
<p>They don't let you use calculator or give an equation sheet on the multiple choice part. So I'm just memorizing the equations on the equation sheet.</p>
<p>And for FR, I hope that they are easy.</p>
<p>I don't really understand E&M.
And I've got to cover fluids, waves, optics, and modern physics today. <em>sigh</em></p>
<p>Crichessill: "in a position vs time graph, if its in negative quadrant, does that mean positive velocity or negative ? how about acceleration"</p>
<p>well velocity = (change in position)/(change in time)</p>
<p>It depends. If it's got a negative slope, then the change in position is negative, time is positive. (-position)/(+time) = (-velocity)</p>
<p>Acceleration = (change in velocity) / (time), (-velocity)/(+time) = negative acceleration.</p>
<p>But that hold true for anywhere, regardless of above or below the X-axis. I think my explanation is correct, anyone agree/disagree?</p>