<p>If four cards are drawn from a standard deck of 52 playing cards and not replaced, find the probabilty of getting at least one heart.</p>
<p>???</p>
<p>If three dice are rolled, find the probability of getting triples -i.e., 1,1,1; 2,2,2; or 3,3,3, and so on.</p>
<p>the answer to this is 6/216 right?</p>
<p>Thank you tons for ur help :-)</p>
<p>lets see...</p>
<p>picking a heart = 13/52 BUT it would be easier to find the complement.
P(at least one heart) = 1-P(getting NO hearts)
1-39/52 = .25 </p>
<p>we're on binomial/geometric distributions right now, so i just know the general formula for probability. can anyone check this?</p>
<p>and for the dice, i think thats right.
6<em>6</em>6 = 216 for the sample space, and there's six ways to get triplets.</p>
<p>correct me if i'm wrong, but k0w, isn't 1-39/52 the probability of getting at least 1 heart IF only 1 card is chosen. however, if 4 cards are chosen then shouldn't it be
1 - 39/52 * 38/51 * 37/50 * 36/49 = .6961</p>
<p>i agree with the triples answer.</p>