<p>PT 5</p>
<p>Pg 657 Section 3 #15,#18</p>
<p>Pg. 672 section 7 #12, #16( why can you move the 4 to a leg), #19( i need a easier way than plugging in), #20</p>
<p>Thanks for the help.</p>
<p>PT 5</p>
<p>Pg 657 Section 3 #15,#18</p>
<p>Pg. 672 section 7 #12, #16( why can you move the 4 to a leg), #19( i need a easier way than plugging in), #20</p>
<p>Thanks for the help.</p>
<p>bro write the question lol or make a pic of the Q</p>
<p>Page 657 section 3</p>
<h1>15</h1>
<p>You have 4 expereince plumbers and 4 trainees. There are two ways to go about solving this question, the first of which is using combinations. </p>
<p>There are 4 Plumbers and we need one on the team. 4C1 = 4 .
here are 4 trainees and we need two on the team. 4C2= 6
4x6= 24. </p>
<p>We can also draw out a diagram.
We will label the plumberss as 1,2,3, and 4 and the trainees as A,b,c, and D.</p>
<p>One plumber for every two trainees.
1AB,1AC,1AD,1BC,1BD,1DC < - six. </p>
<p>6x4=24.</p>
<h1>18</h1>
<p>There's quite a few posts regarding this question, search them up. They all have fairly thorough explanations. I also made a help post for this question so search it up in my history. </p>
<hr>
<p>Page 672</p>
<h1>12</h1>
<p>Slope is rise over run AKA change in Y over change in X. The only possible candidates for a negative slope are OB,OA, and DC. We find that DC is -1 because rise=2 and run=2 2/2 = 1. The slope is negative. Thus -1.</p>
<h1>16</h1>
<p>This one deals with Poroportions of similar triangles.</p>
<p>16 mi is four times 4 mi.</p>
<p>the 15 mi can be labeled as X+4X because 4x/x= 4 as well. X happens to be 3, so you will apply pythagorean theorem to find your answer.</p>
<h1>19</h1>
<p>x^-4/3 = k^-2 means K = X^-2/3 because X^-2/3 +X^-2/3 = X^4/3 .
We want to find (xy)^-2/3.
which is X^-2/3 x y^-2/3</p>
<p>Lets find X first.</p>
<p>Since we know k^-1 = x^-2/3 , we already solved part of the question. since it can also be expressed in terms of K as 1/K </p>
<p>Now we want y ^-2/3 </p>
<p>Using the same method as before, we know that Y^2/3 = n , but thats not negative. So how do we make y^2/3 into y^-2/3? we take the negative reciprocal. Thus y^-2/3 = 1/n </p>
<p>1/n x 1/k = 1/nk </p>
<h1>20</h1>
<p>This question takes about two seconds to solve.</p>
<p>Look at the graph, its been shifted. 3 right and 2 down. </p>
<p>to move right, we subtract from X-in this case, its -3 . We move down, so its -2.</p>
<p>-3 x -2 = 6.</p>