<p>How do you solve these types of problems? </p>
<p>Question: In the x-y coordinate system, ( square rooot 6, k) is one of those points of intersections of the graphs y= x^2-7 and y = -x^2 + j where j is a constant. What is the value of j? </p>
<p>(A) 5
(B) 4
(c) 3
(D) 2
(E) 1 </p>
<p>Thank you for your help!</p>
<p>Ok, set the two functions equal to each other, and plug in square root 6 for x. Then solve for j.</p>
<p>So you should get A as the answer...</p>
<p>it's really easy.....
put the value square root 6 and k respectively to x and y in the equation y=x^2-7 and get k=-1....that means y=-1 in that point.....now put square root 6 and -1 respectively for x and y to find j......j=5...so the answer is (A)5</p>
<p>hey,lolcats method is superior to mine</p>
<p>Yeah whenever you hear "intersection" and have two functions (y=...) ALWAYS set them equal to each other. 99% of the time that's exactly what the question is asking for.</p>