<p>can someone help me with number seven on page 549 . i know it's easy, bnut i cant figure it out</p>
<p>thanks in advance</p>
<ol>
<li>If a, b, and c are different positive integers and (2^a)(2^b)(2^c) = 64, then (2^a) + (2^b) + (2^c) = ?</li>
</ol>
<p>a. 14
b. 17
c. 21
d. 28
e. 34</p>
<p>(2^a)(2^b)(2^c) = 64 is the same as (2^(a+b+c)) = (2^6). That means that a+b+c = 6. </p>
<p>Because a b and c are different positive integers, what 3 positive integers add up together to equal 6? 3 2 and 1 do. Plug that in to the second equation.</p>
<p>(2^a) + (2^b) + (2^c) = ?
2^3 + 2^2 + 2^1 = ?
8 + 4 + 2 = 14.</p>
<p>Answer: a) 14</p>