<p>I'm somewhat confused on this problem. So any help would be great. Thanks</p>
<p>Somebody will post an algebraic solution, but if you are not comfortable with transformations you can always plug in good numbers.</p>
<p>Set the first term t=30,
the second term is 3 + (1/3)30 = 13.
The ratio of the second term to the first one is 13/30.
Which answer choice would give you 13/30 for t=30?
A, B are too big, E is negative.
Is it C or D then? You decide.</p>
<p>==================
Quick guessing approach (no 100% guarantee).
Out of the five choices only C and D include t in the denominator, so A, B and E are out.<br>
D can be ruled out because it has t+3 in it, and "3 greater than..." is featured in the question (find how Xiggi explains dealing with this kind of a situation).
That leaves C.</p>
<p>3 GREATER than a third of the first term = 3 GREATER than a third of t = t/3 + 3</p>
<p>So the second term is t/3 + 3. We know the first term is t.</p>
<p>The answer is: (t/3 + 3) / t = [(t + 9) / 3] / t = (t + 9) / 3t = C</p>
<p>If you do the above on paper, it is quite fast.</p>