<p>thanks......................\
just press on the chat room and type: APcalc</p>
<p>What the heck? Please, someone teach me how to join a chatroom on AIm?
I can't find a chatroom joining button anywhere on the menu thing. Where is it?</p>
<p>I need help w/ this question...</p>
<p>Given this table:
x | 0 | 1| 2|
f(x) |1| |k| 2|</p>
<p>The function f is continuous on the closed interval [0,2] and has values that are given in the table above. The equation f(x)=1/2 must have at least two solutions in the interval [0,2] if k =</p>
<p>A) 0
B) 1/2
C) 1
D) 2
E) 3</p>
<p>A.</p>
<p>because it means that it has to curve down (from 1 to 0) and back up (from 0 to 2), meaning that it would have to pass y=1/2 twice. =]</p>
<p>AIM tab in the menu, chat, buddy chat, change name of room to APcalc and invite yourself.</p>
<p>ty. that was extremely easy... I just totally overthought it...</p>
<p>I have an urgent question. If they give you the graph of the 1st deriv,f'(x), and they ask you the average rate of change, is it MVT for integrals or for derivs?
I'm really puzzled with this since I thought that average rate of change was MVT for derivs and average value was MVT for integrals, but I got many MC and FRQ mocks wrong because it seemed that in some cases it was MVT for integrals even when it said "average rate of change".
Any help is appreciated</p>
<p>Where can I get a worksheeet or website with some notes on area under the curve and rotating a shape around the x, y, or # axis? Oh, and cross sections.</p>
<p>@ alwaysinsession: YouTube</a> - Solid of Revolution (part 1)</p>
<p>This video followed by all the other parts to it really helped me. Instead of just giving an equation and plugging in, he helps you learn the theory behind it, to the point where you (technically) don't need to memorize the equations.</p>
<p>what is the integral from 0 to pi/4 of e^tanx/ cos^2x ??</p>
<p>A)0
B)1
C)e-1 (the answer should be C, but I don't know how to work it out)
D)e
E)e+1</p>
<p>@ AMS101: Is it a no-calculator problem?</p>
<p>Ohhh, I get it. Set U=tanx
Therefore, du=sec^2(x)dx
So...cos^2(x)du=dx
So, the cosines cancel and you are left with e^udu evaluated from 0 to pi/4
So, it integrates into e^tanx evaluated from 0 to pi/4, so that is e^1-e^0</p>
<p>hey can anyone explain question # 4 on the collegeboard 2006 Form B exam....I don't understand part B...(arne't you supposed to search for max/min using hte first derivative)?
thanks
AP:</a> Calculus AB</p>
<p>Hey guys, is there a way to find critical pts when they give us a trig function (IE: 82sin(t) - sin(t^2))</p>
<p>I try my zeros and solve functions but sometimes, all I get is a bunch of #s like </p>
<p>234 @ 34234 (something like that)</p>
<p>Btw, Im using a ti-89. Thanks.</p>
<p>@hereicome, take the derivative of f(t).......</p>
<p>@john203, graph the deriv of the function and find zeroes</p>
<p>can anyone help me on my question....</p>
<p>I have an urgent question. If they give you the graph of the 1st deriv,f'(x), and they ask you the average rate of change, is it MVT for integrals or for derivs?</p>
<p>I'm really puzzled with this since I thought that average rate of change was MVT for derivs and average value was MVT for integrals, but I got many MC and FRQ mocks wrong because it seemed that in some cases it was MVT for integrals even when it said "average rate of change".
Any help is appreciated</p>
<p>@hereicome: Have you look at this?</p>
<p>average rate of change is just the integral of f'(x) divided by the change in x</p>
<p>somedumbnoob, so if the problem said "Find the average value of f'(x)", you would just have to find MVT for derivatives, right?</p>
<p>I don't know where you're getting MVT from. I don't see how this relates to MVT at all except that it has a somewhat similar equation to it.</p>