calc bc help please! :)

<p>can you solve this problem for me please?</p>

<p>i have to find the indefinite integral of...
integral of (2x+1)/(square root of (x+4))dx.....</p>

<p>i tried u-substitution but it's not working....</p>

<p>thanks in advance!</p>

<p>According to the lovely TI-Nspire CAS, the answer should be:</p>

<p>(2 (square root of x+4) times (2x - 13)) as the numerator and 3 as the denominator</p>

<p>Hope this helps!</p>

<p>thanks…but unfortunately im not supposed to use the calculator.</p>

<p>do you know how to do it by hand? any help from anyone would be greatly appreciated :)</p>

<p>When you u substitute, u=(x+4), separate the simplified part from (u^(1/2))(2u-7) to (2u/u^(1/2) - 7/u^(1/2)). Then integrate and solve.</p>