Calculus BC help--

<p>The question was something along the lines:</p>

<p>Evaluate dy/dx=(y^2-y2)cosx y(2)=1</p>

<p>The answer choices were like this
ln |y-x| + ln |2| = 2sinx +sinx</p>

<p>And stuff like that.</p>

<p>How do I go about doing this...do it have to separate it using partial fractions?</p>

<p>no</p>

<p>make differential equations... dy/(y^2-2y? i presume)=cosxdx then you take the integral of both sides...i don't know how they got their answer, but when you solve differential equations, u shouldn't haev x's and y's together like that</p>

<p>Whoops, I mean for the for ln, instread of ln |y-x| i mean ln |y-2|</p>

<p>Also, how about this one?</p>

<p>We are given two equations:
f(x)=x^3-3x^2</p>

<p>g(x)=6x^3+3x</p>

<p>I'm supposed to evaluate these little-ohs and big-ohs of any possible relatinoship between these two, like is f=o(g) f=O(g) or g=o(x) g=O(x)...stuff like that.</p>

<p>ohh put them over each other... contineu to take derivs until u read a dead end... as u go to infinity if f/g approaches 0 then f little of of g... if any number >0 the f big oh of g</p>

<p>how is this bc? I am taking ab right now...... you can do this through solving differential equations and plugging in the needed values</p>

<p>no... u can't do that... with f o of g? that's l'hopital's rule for indeterminate forms... not the problem asked... but u don't cover this in ab</p>