<p>How do you find the antiderivative of f(x)=(sinx)/(1 - sin2(x))?</p>
<p>good question, I just finished derivatives in Calc.; I wouldn't be able to tell you. look in textbook or prep. book</p>
<p>If the denominator is supposed to be 1-sin^2 (x), then you can use the trig identity sin^2(x) + cos^2(x) = 1 to change it to cos^2(x). So now you have f(x) = sin(x)/cos^2 (x) = tan(x)/cos(x) = tan(x)sec(x).</p>
<p>Now, all you have to do is integrate f(x) = sec(x)tan(x). If you remember that the derivitive of sec(x) is sec(x)tan(x), then the antiderivitive of sec(x)tan(x) is sec(x)</p>
<p>Oh duh I should have remembered that from trig. Thanks.</p>