<p>well its been 48 hours...but they still havent released the questions...</p>
<p>i guess this will be the link whenever they get around to it:
<a href="http://apcentral.collegeboard.com/members/article/1,3046,152-171-0-1998,00.html#name06%5B/url%5D">http://apcentral.collegeboard.com/members/article/1,3046,152-171-0-1998,00.html#name06</a></p>
<p>anyways...talk away!</p>
<p>This was the only hard part of the short answer, does anyone have all of the answers to part IV</p>
<p>Ni (2+) + OH- ------ Ni(OH)2</p>
<p>C6H14 + O2 --> CO2 + H2O</p>
<p>I think another one was
HC2H3O2 + OH- --> H2O + C2H3O2-</p>
<p>Cu2+ + Zn-----> Cu + Zn2+</p>
<p>For that equation with acetic acid, doesn't it dissociate into H+ and C2H3O2-?</p>
<p>Wouldn't the net ionic equation just be H+ + OH- ---> H20?</p>
<p>No...its not a srtong acid...</p>
<p>How many points would you lose for just H+ + OH- --> H2O? Would you lose all 3? I put that also with the HF one even though I knew they were weak, stupid me, because I thought all aqueous could be split :(.</p>
<p><em>Ahem</em></p>
<p>1.
a) i. Ksp = [I-]^2[Pb2+]
ii. 2.6E-3
iii. 8.8E-9
b) [Pb2+] = 1.3E-3 [I-] = 2.6E-3 (A saturated solution will always have the same MOLAR CONCENTRATION in solution. Doubling the volume will double the AMOUNT of moles in solution, but not the MOLAR CONCENTRATION.)
c) Decrease; cite the common ion effect or LeChatelier's principle
d) i. 4.1E-6
ii. Q = 1.7E-11 < Ksp (1.2E-10); since Q < Ksp, no ppt forms</p>
<p>3.
a. i. .6112 g C
ii. .3564 g N
iii. .2035 g O
iv. C4H5N2O
b. i. 188 g/mol
ii. C2H4Br2</p>
<ol>
<li><p>a. Compound X = Na2CO3; Compound Y = KCl; Compound Z = MgSO4
b. Mg(OH)2
c. Rxn: CO3-2 + H2O --> H2CO3 + OH-; increase in OH- concentration pushes pH above 7
d. Measure 33mL of stock soln with 50mL buret. Add 33mL stock soln to 100mL volumetric flask. Add distilled water until volume of soln is about 98mL. Use dropper to add distilled water until meniscus reads 100mL.
e. Lots of answers to this one. The SIMPLEST: Add both solids to water and stir. The one that dissolves is Na2CO3, the one that does not dissolve is CaCO3. </p></li>
<li><p>a. i. H-bonding, dipole-dipole ii. LDF
b. Glucose is polar and thus soluble in water (likes dissolve likes, polar molecules dissolve in polar liquids like water. Cycolhexane is nonpolar and thus does not dissolve in polar liquids such as water.
c. i. Process 1: Intermolecular H-bonds must be overcome. Process 2: H-O bonds must be broken.
ii. Disagree; when H2O boils, the intermolecular H-bonds must be overcome, but the H-O bonds remain intact.
d. i. Diagram 2: uncatalyzed reaction; Diagram 1: catalyzed reaction
ii. Disagree; adding a catalyst does not add any energy to the system, it simply provides an alternate path for reaction with a lower activation energy than the normal reaction. </p></li>
<li><p>a. 8s1
b. Q would be a metal, as it would lie at the bottom left of the periodic table. Additionally, all elements with their outermost electron in the S orbital are metals.
c. Q would have the largest atomic radius in its group because the periodic trend of atomic radius is decreasing as you move from left to right; this is supported by the fact that the Q atom would have an immense amount of shielding which would push valence electrons farther away from the nucleus.
d. +1
e. Q + H2O --> H2(g) + QOH
f. i. Q2CO3
ii. The compound would be soluble in water because all IA cations are always soluble in water.</p></li>
</ol>
<p>Bam.</p>
<p>And killernago, you would get no credit for writing that. You have none of the reactants or products correct.</p>
<p>WOW......zspot9.........our answers were almost identical!!!!!!!!!! Do you have answer for #7?</p>
<p>Um guys the question was Ch3cooh (aq) + Ba(oh)2 (aq) --> ? </p>
<p>Well Bach3coo- is (AQ) so its a spectator thing isn't it? so I ended up with H + oh --> H2o. Who knows maybe I will get a point for it because they DO show leniencey. Ok check me on the rest of the reactions</p>
<p>Kclo3 --> kcl + o2
Cu2+ + zn --> Zn 2+ + cu
Ni 2+ + oh --> Ni(oh)2 (is this a complex?)
C6H14 + o2 --> co2 + h2o</p>
<p>for number 2 I got like -257 for delta G. And so I got 1.47 X 10^45? Can someone veryifty this for me. thanks.</p>
<p>I have answer for number 7
F
|
:S-F
|
f</p>
<p>Sp3
its less than because of the replusion effect (missed this. i cant believe it )</p>
<pre><code> F
| :
F- S -F
F F
</code></pre>
<p>its d2sp3. </p>
<p>square pyramdial</p>
<p>Finally its 4 + for the charge.</p>
<p>I didn't do 2 or 7. I could do them for you...but I'm not THAT motivated... :p</p>
<p>Wait the first one is trig. pyramidal.</p>
<p>Anyhow I have a funny story to tell. When I first read 7 I thought they were asking to write the dott structure for
SF3BH3</p>
<p>You guys try and do that lol... It took me a while to realise. </p>
<p>Oh and please will someone make a "point" guide to explain the point system and how much each part was? Please I will be grateful :d.</p>
<p>K isn't equal to 10^45. that would mean it was fully dissolvable..... PbI = not dissolvable.</p>
<p>zspot, we have a lot of the same answers....... good :) I think I missed a couple things:</p>
<p>5d: didn't use the dropper at all, just said fill to 100mL....... might lose a point.
6.i. I also put LDF for the forces.... wouldn't that be a legal choice?</p>
<p>i think also for b and c I just worded it differently.... might've screwed it up though.</p>
<p>8a. I feel like I put 6s1 for some reason..... maybe I did, maybe I didn't..... idk.
e. I put Q+ + OH- cause it would be soluble....... and I balanced it, didn't we have to do that?</p>
<p>Guys can someone also tell me the "average" curve? I want to know! f or a five</p>
<p>Lol.. i ment the 45 for number 2. Guys for number 5 the last part, would mixing them with h2so4 work because caso4 precips whereas naso4 doesnt? Please tell me.</p>
<p>Evilbooyaa:</p>
<p>for 6.a.i., LDF forces are present, but the predominant forces of attraction are H-bonding, followed by the second most prevalent, dipole-dipole. LDF forces are present between any molecule, but generally when it asks for the IMFAs it means the strongest one. You may still pull a point out.</p>
<p>For 8e, I meant to write my Q+ + OH- dissociated, but I think that I forgot to balance it on the test. :( So you're right on that one.</p>
<p>i could verify i got 10^45 as well.</p>
<p>net ionic number 2 silver chloride added to hydrochloric acid? what the hell was thatt?</p>