<p>can you explain the following question?</p>
<p>Which of the following solutions is the product of the neutralization reaction between 10 ml 0.2 M KOH and 10 ml 0.2 M HI?</p>
<p>a) 0.1 M KI (answer)
b)0.2 M KI
c)0.4 KI</p>
<p>they react in a 1-1 ratio. So, you have (.01)(.2) mol (.002 mol) KOH and .002 mol HI. When they react, it produces the same number of moles of KI (.002 mol).</p>
<p>But, now, we have a new concentration, because you added 10ml to 10ml = .02L</p>
<p>So, the molarity of KI is .002mol / .02L = .1M</p>