<p>Who is ready?</p>
<p>im not ready. the title of this thread is too intense @_@</p>
<p>neither am i… I need help lol</p>
<p>i’ve been taking a bunch of practice tests and i dont understand this (incredibly simple) question</p>
<ol>
<li>Which gaseous product is formed when dilute nitric acid reacts with silver metal in the absence of air?</li>
</ol>
<p>A. H2
B. O2
C. NH3
D. NO</p>
<p>I would say A. H2.</p>
<p>When you have an acid that reacts with a metal, it will produce hydrogen gas and, in this case, silver nitrate.</p>
<p>this is what i thought as well…
the answer is D. NO.</p>
<p>I would say D.</p>
<p>H2NO3 + Ag = NO + H2O + Ag</p>
<p>just looked it up in barron’s. it is on a list of common oxidizers/reducers. guess you just need to memorize those</p>
<p>Can Boron have a filled octet of 8 despite it being an exception to the octet rule and only needing 6?</p>
<p>In one of the past exams a question asks for the geometry of BF4- which obviously requires 4 bonds from boron and gives tetrahedral geometry but I didn’t know boron was capable of doing this</p>
<p>Boron is capable of forming 4 bonds since it has the orbitals for it. It just tends to forms 3 when it’s in isolated compounds like B2H6 or BCl3. But when it’s combined with other stuff like (Cl)3B-NH3 or an ion like BF4-, it can form 4.</p>