Chemistry Problem Question....Urgent!!

Pre-College Issues High School Life
1

<p>Plz help me on this problem. I have no clue how to do it, im not even in AP Chem. Its for my friend. Thank you, this is urgent.</p>

<p>I coudnt do subscripts or superscripts, sry.</p>

<p>HC3H5O2 <--> C3H5O2 + H+ K= 1.34 x 10^-5</p>

<p>1.) Propanoic Acid ionizes in water in the according to the equation above. </p>

<pre><code> a.) Write equilibrium-constant expression for the reaction.

  b.) Calcualte pH of .265 M solution of propanoic acid.

  c.) .496g NaC3H5O2 is added to 50 mL sample of 0.265 M Solution of propanoic acid.
              i.) Concentration of C3H5O2
              ii.) Concentration of H+

</code></pre>

<p>HCO2 + H2O <--> HCO2H + OH-</p>

<p>d.) Given that [OH] is 4.18 x 10^-6 in .309 M solution of Sodium Methanoate, calculate the following:
i.) Value of Kb for HCO2
ii.) Value of Ka for HCO2H</p>

<p>e.) Which acid is stronger, propanoic acid or methanoic acid? Justify your answer</p>

<p>Id GREATLY appreciate if anyone could do this and give a brief explanation. This is worth alot</p>

2

<p>a) K = [C3H5O2][H+]/[HC3H5O2] <-- concentrations of products over reactants</p>

<p>b) do an ICE table</p>

<p>HC3H5O2 <--> C3H5O2 + H+ K= 1.34 x 10^-5
I .265 0 0
C -x +x +x
E .265 x x</p>

<p>Using K, (x)(x)/(.265) = 1.34e-5, so x = .00188, which is the concentration of H+, which controls the pH</p>

<p>pH = -log[H+] = -log(.00188) = 2.725</p>

<p>That's all I feel like doing right now. I have chem homework to do, too. :&lt;/p>

3

<p>damn, anyone else?</p>

<p>thx for the help theone, tho.</p>

4

<p>Picking up where theoneo left off:</p>

<p>C. You have to calculate the what .496 of NaC3H5O2 equals ( in this case it's) 0.005163. Now you have you divide the by 0.050 and add it to the original concentration of acid. You would arrive at .368. Setting up the ICE table should ultimately yield 0.002214 M for both since it's in a one to one ratio. <strong><em>Check my work its late</em></strong></p>

5

<p>Gotta stop
MAKE URGENT, URGENT</p>

<p>EMERGENCY!</p>