<p>My question concerns this homework problem I have: </p>
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<p>"How many unpaired electrons are there in the following transition metal ions. Write your answer as a sequence of numbers, for example, 23542141. </p>
<p>A) Mn5+ B) Fe3+ C) V5+ D) Fe4+ E) Mn4+ F) Ni4+ G) Cu4+ H) Sc2+ I)Fe2+ " </p>
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<p>My text wasn't really helpful. So, wouldn't these be the answers for e/one? 25043651 </p>
<p>For example, for Mn5+ I picked 2 (2 unpaired e-'s) b/c the config. is 4s2 3d5. so that is 5 + 2 = 7 unpaired electrons, minus 5 (Mn5+) = 2. Is this the right way to think about it? </p>
<p>And for instance, for V5+ I said..... since it's s2 d3, that = 5 unpaired electrons, and so 5-5 = 0. So am thinking it through the right away? And what about Cu4+, since it is one of the exceptions having a config of s1 d10? </p>
<p>Thanks in advance for any help</p>
<p>OK haha that's perty easy i think...let's c
Mn...so write the configuration for it...then subtract 5 electrons...do you guys write down the little dashes withdouble arrows over them? do that and in the last level if there is an arrow without a pair is left then the number of unpaired arrows is what you are looking for...did that help or confuse...here i'll make a visual..let's do Na-4</p>
<p>' ' ' ' ' ' ' ' ' ' ' ' ' ' ' </p>
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<p>Since Na is 2 2 6 1 you add 4 more and you get 2 2 6 2 3...so there are three unpaired electrons</p>
<p>P.S> did i understand your question right? hopefully</p>
<p>thank you, i got it!</p>
<p>i've another question: at 19.0 degree C a liquid has a 40mmHg vapor pressure; its normal boiling oint is 78.3. what is its enthalpy of vaporization in kJ(mol)^-1</p>
<p>the answer is 42 kJ(mol)^-1</p>
<p>but i have no idea how to get to the correct answer, please help. thank you</p>
<p>Oh...i don't remember how to do that problem... i remember coveering something about enthalpy a couple of months ago but we never did the problems with it...sry</p>
<p>Good luck...if you'll figure it out tell me plz LOL
{{{{HUG}}}}</p>