Did Gruber's get a math problem wrong?

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1

<p>There are actually two, but they are very similar. Notice the spaces I have between the fractions. </p>

<p>a/b / c = ?</p>

<p>Answer was ac/b. I think this is wrong. When you plug in 1/4 for a/b and 6 for c you get .041666 which is the same as 1/24 which would be equivalent to a/bc. Usually I solve it like a/b / c = a/b * 1/c = a/bc</p>

<p>Another question said a / b/c = a/cb which is also wrong I think. Shouldn't you solve it like a / b/c = a * c/b = ac/b? Why did these mix up? The spaces are exactly the same as they are in the book.</p>

2

<p>I assume you mean a/b is in the numerator and c in the denominator. In this case (a/b)/c=(a/b)x(1/c)=a/(bc). </p>

<p>And your second answer looks correct.</p>