<p>what is the domain of the square root of x+5 divided by x+2?</p>
<p>if it is sqrt(x+5) / (x+2), then all reals except -2</p>
<p>if its sqrt( (x+5)/ (x+2) ), then x > -5 but not equal to -2</p>
<p>If (root (x + 5)) / (x + 2), then all reals >= -5 except x = -2.</p>
<p>If root ( ( x + 5 ) / (x + 2)), then:</p>
<pre><code> all reals > -2
and
all reals <= -5.
</code></pre>
<p>I'm so confused which one is it
the exact problem is the sqaure root of x+5 divided by x+2</p>
<p>Repeating your problem in <em>exactly</em> the same format as you did the first time is a waste of time, yours and everyone else's.</p>
<p>Sounds like you just want someone to give you a number for an answer, rather than going through the two excellent answers you already have.</p>
<p>Did you post the exact problem, precisely the same, as it is written in your source? There weren't any parentheses? There wasn't a square root sign?</p>
<p>i don't know how else to put it the square root of (x+5) was in the numberator and the quantity (x+2) was in the bottom</p>
<p>and how would that be written in interval notation?</p>
<p>OK. You are not permitted to divide by zero, so the denominator cannot be zero. (x + 2) not equal to zero means that x is not equal to -2.</p>
<p>The square root function is defined only for numbers greater than or equal to zero in the real numbers. So (x + 5) must be greater than or equal to zero. In other words, x must be greater than or equal to -5.</p>
<p>Both of these requirements must be satisified. Therefore, the domain consists of all real numbers greater than or equal to -5, except -2.</p>
<p>AngelFlower:
Putting it as sqrt(x+5) / (x+2) would have made it pretty clear.</p>
<p>As for interval notation, use post#3;
-5 <= x < 2
and 2 < x (or 2 < x <= infinity, if you insist on an upper 'limit')</p>