<p>If the sum of four consecutive odd integers is "s" then in terms of "s", what is the greatest of these integers? </p>
<p>A- s-12 divided by 4</p>
<p>B- s-6 " " " " " " " </p>
<p>C- s+6 " " " " " " "</p>
<p>D- s+12 " " " " </p>
<p>E- s+16 " " " " </p>
<p>So let the numbers be 1,3,5, and 7. Their sum, or "s" = 16.
Barrons say the answer is D.
16+12= 28 28/4= 7</p>
<p>My answer was E.</p>
<p>16+16= 32. 32/4= 8</p>
<p>This is an error from the book, right?</p>
<p>Your answers didn't print right in your post, but from your writing I think I was able to decipher that they were all supposed to be divided by 4. </p>
<p>Actually, the answer is D.</p>
<p>Consider: an odd number is a number of the form 2n+1</p>
<p>then the sum of 4 consecutive odd numbers =</p>
<p>(2n+1) + (2n+3) + (2n+5) + (2n+7) = 8n + 16</p>
<p>in choice D, assuming it D is (s+12)/4</p>
<p>8n+16+12 = 8n+28
(8n+28)/4 = 4(2n+7)/4
= 2n+7</p>
<p>which was the biggest number we added.</p>
<p>Besides, how is 8 right if the biggest number you added was 7? You answered your own question.</p>