<li> Order the elements S, Cl, and F in terms of increasing atomic radii.
(A) S, Cl, F
(B) Cl, F, S
(C) F, S, Cl
(D) F, Cl, S
(E) S, F, Cl</li>
</ol>
<p>the answer should be d, but they say it is E</p>
<p>here is their explain:
9. E </p>
<p>Remember, atomic radii decrease moving across a period from left to right. This is because protons are added to the nucleus and these protons attract the electrons more strongly, pulling them in tighter and decreasing the atomic radius. Atomic radius increases moving down a group or family, however, because the value of n increases as you add another shell, the electrons spend more time away from the nucleus, dissipating the attraction between nuclear protons and themselves. Since fluorine and chlorine are both in the same group but chlorine is below fluorine, we know that chlorine is bigger than fluorine. Sulfur is to the left of both chlorine and fluorine, so it must be the smallest of all. Arranged in order of increasing size, they are S, F, Cl, or answer E.</p>
<p>the sentence below is so wrong:</p>
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<p>we know that chlorine is bigger than fluorine. Sulfur is to the left of both chlorine and fluorine, so it must be the smallest of all</p>
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<p>why the heck should S smaller? s should be bigger since its nucleus is less abtractive then F and Cl. and S and Cl are in the same period</p>