<p>Okay. People say 8 and people say 6. I think 8 is wrong because then green is greater than red which is not what the problem said. 6 i THINK i wrong too because to start out with you have 22 red and 21 Green marbles so the answer i thought was 0. I originally put 6 too, but i changed it to 0 because of this. If 0 is wrong, can anyone tell me the reason why?</p>
<p>O yea... and for that 4+ rectangle problem. I put 4 because the area has to = 12? and only 6 values work and two is already used. So i thought the answer was 4. But actually i might be wrong.</p>
<p>There are 25 red and 25 green. You take out 3 red and 4 green. You take out 13 more. What's the minimum number of reds to remove and have more reds than green.</p>
<p>If you take 6 red (and 7 green), you end up with 9 red and 11 green total.</p>
<p>If you take 7 red (and 6 green), you end up with 10 red and 10 green total.</p>
<p>If you take 8 red (and 5 green), you end up with 11 red and 9 green total. ^^^^^Ding ding ding! We have a winner!</p>
<p>3 red 4green
(1 red marble+3)=4 red /////// (13 original -1 red marble)+(4)=16 green
(2+3)=5 red/////// (13-2)+(4)=15 green
(3+3) = 6 red ////// (13-3)+(4)=14 green
(4+3) = 7 red ////// (13-4)+(4)=13 green
(5+3) = 8 red ////// (13-5)+(4)=12 green
(6+3) = 9 red ////// (13-6)+(4)=11 green
(7+3) = 10 red ///// (13-7)+(4)=10 green
(8+3) = 11 red ///// (13-8)+(4) = 9 green</p>
<p>^^ at this point, red greater than green. So at least 8 of the 13 beads must be red in order for red ro be > green/</p>
<p>you're reading the damn question wrong. there are 3 red and 4 green. then there are 13 UNKNOWN. How many of those UNKNOWN must be red in order for red > green.</p>
<p>yea... o my gosh man... nvm. I still think it's zero. I KNOW there is 13 unknowns and there were actually 4 greens. but still either way, there is GOING to be more red marbles in the first place because you subtracted 3 and 4 from the 25 and 25. it can be ALL green!!! and no reds taken out and it's going to be bigger.</p>
<p>I read it over a few times and didn't see why it should be anything different. 8 would work if you did it the other way, but this was a pretty crappy question.</p>
<p>Actually, on second thought CB doesn't include numbers you don't use. The rectangle inside of a circle problem gave the perimeter so you know that a rectangle could actually fit.</p>
<p>In this case, I believe they give you 25 of each so you know that you won't run out of one color or another.</p>
<p>The answer is 8. I thought the only trick would have been putting 7. If there were 7, then they'd be equal.
The point to the 25 is just saying that you wont run out of a certain color. They could have said a 100 of each, its just to eliminate stipulation cases.</p>
<p>There are 25 red/ 25 green in a jar. A person takes out 3 red, 4 green. THen he takes out 13 more, how many of those 13 have to be red for there to be more red marbles than green marbles out of the jar.</p>