<p>Help me do this basic question!</p>
<p>During the electrolysis of fused NaCl, which half-reaction occurs at the negative electrode?</p>
<p>A) Na+ + e- ==> Na0
B) 2Cl- ==> Cl20 + 2e-
C) Na0 ==> Na+ + e-
D) Cl20 + 2e- ==> 2Cl-</p>
<p>What is the answer? and please explain! I can't figure out which is the anode and which is the cathode... Na and Cl are in different columns in table J of the reference table.</p>
<p>ok so the first thing to remember is in electrolysis, the anode is postive and the cathode is negative…so if it’s asking for the negative electrode, that means reduction will be happening there…reduction is the gaining electrons so the answer is A.</p>
<p>lols i was wrong</p>
<p>yes, but D is also gaining electrons. Why can’t D be the answer?</p>
<p>Note: The answer is A btw</p>
<p>It would be Cl-1 in solution, not Cl2.</p>
<p>What is the negative electrode? The way the - ions from the salt bridge are going?</p>