<p>Hi everyone,
These are some questions I've been having a lot of trouble figuring out. Can you guys help me?</p>
<p>At a company, there are n more male employees than female employees. If there are k male employees at the company, what fraction of the employees are male, in terms of n and k?
a. 1/(2k+n)
b. k/(k+n)
c. k/(2k-n)
d. n/(2k+n)
e. (k-n)/2k
The answer is C. Why?</p>
<p>Red apples cost $0.25 and green ones cost $0.35.
Ms. Jones bought twice as many red apples as green apples. If she spent $7.65 on these apples, how many green apples did she buy?
a. 9
b. 13
c. 18
d. 22
e. 27
The answer is A, but I got it by working backward and plugging in the answers. Is there another easier way?</p>
<p>Thanks!</p>
<p>There are k male employees so the numerator is k.</p>
<p>Since there are n more male than female, the number of males (k) is females + n:</p>
<p>k (male employees) = f (female employees) + n</p>
<p>solve for f:</p>
<p>f = k - n</p>
<p>Total number of employees = k (male) + f (female)</p>
<p>substitute k-n for f:</p>
<p>Total = k + k - n = 2k - n</p>
<p>answer = k / (2k - n)</p>
<p>Set up two equations:</p>
<p>.25R + .35G = 7.65</p>
<p>R = 2G</p>
<p>Substitute 2G for R:</p>
<p>.25(2G) + .35G = 7.65</p>
<p>.85G = 7.65</p>
<p>G = 9</p>
<p>For the first, u want (male)/(male+female)
Male is given as K. There are n more males than females. So females is (k-n).
Now add those.
K-N+K=2K-N
So answer is K/(2K-N)
For the second, there is most probably a way. But plugging in is ur best option. Believe it or not, its saves alot of time and is easier. Its faster to type in some numbers into ur calc than to solve some algebraic equation</p>
<p>Thanks guys, that really helped! Yes, I’ve found plugging in to be my best option for many problems.</p>