<p>Zemunska</a> gimnazija</p>
<p>number 8</p>
<p>please explain why too</p>
<p>All of the triangles have the same “base,” OX. Because the area of a triangle is (1/2)<em>base</em>height, you want to find which point (A, B, …, E) yields a triangle with base OX and minimal height. Just by looking at it, point A works, so the answer is A.</p>
<p>BB pg.369-#8
The figure above shows a portion of the graph of the function f. If f(x+5)=f(x) for all values of x, then f(x)=0 for how many different values of x between 0 and 12?
A. Eight
B. Nine
C. Ten
D. Eleven
E. Twelve</p>
<p>can some1 explain this</p>
<p>I don’t have the blue book</p>
<p>i think something is wrong with the gradeing, i put A, but it said 0 next to it???</p>
<p>Yeah, I’m not gonna trust that grading, particularly since many of the questions have misspelled words or bad grammar.</p>
<p>As to firelions question, i read the answer key and i think this is how you solve it, since f(x+5) is the same as f(x) for 0, there are four values for f(x) in the current graph in the picture. if you transform it 5 to the right, the value would become 0( look at the grpah). Then, they ask for the values from 0-12, and it has four intersections or0’s, until five, and then you repeat the grpah, so you have eight intersections and nowyou are at 10 on the number line. that eight plus the intial 0 when you translated the grpah should give you nine, sorry if this is confusing, best i could explain it online…=)</p>
<p>Clearly, f(x) is periodic with period at most 5, but I can’t say much else (don’t have the BB).</p>
<p>i don’t understand 14. where are X and Y, and what is the question asking for?</p>
<p>okay, i don’t trust this site. #19 none of the answers were actually correct.</p>
<p>X and Y are probably the opposite vertices…in that case the answer’s 6…</p>
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<p>f(x)=f(x+5). Since if you add to x you must go to the left by elementary algebra, (just as if you add to y you have to go up; eg. f(x)+5 is f(x) translated upwards 5 units) f(3)=f(-2) and f(4)=f(-1) and so on. Therefore, you can safely assume that f(x) repeats itself(like the sine or cosine wave repeats itself) every 5 units. We must find f(x)=0 for all values 0 to 12. f(x)=0 for 4 times when x is 0 to 5(you find this by counting all the times f(x) or y is 0); since f(x) repeats, f(x)=0 for 8 times from 0 to 10. How many times is f(x)=0 from 10 to 12? Since f(x)=0 1 time from 0 to 2 and f(x) repeats every 5 units, the answer is 1. 8+1=9, 9 is the final answer.</p>