<p>Help me on this Math IC question: how do you solve it and what is the answer?</p>
<p>which value of k makes it so that there are two possible solutions</p>
<p>2.31x^2 + kx + 5.1 = 0</p>
<p>i tried it in a calculator...the parabola crosses the X axis when k is 8 or higher...the two possible answers(when k is X) is -1.81 and -1.22 hope that helps</p>
<p>u have to remember that for there to be two distinct real solutions, the discriminant (b^2 - 4ac, or is it determinant? i always get those two terms confused) has to be more than 0.</p>
<p>so... b= k, a = 2.31, c = 5.1</p>
<p>k^2 - 4(2.31)(5.1) > 0 --> k^2 > 47.124</p>
<p>so k has to be about 7 or more.</p>