<p>ImageShack</a> - Hosting :: picture1ms0.png
answer = 2.5</p>
<p>ImageShack</a> - Hosting :: picture2xt9.png
answer = E</p>
<p>those are the only two i missed on the math section. any help on em?</p>
<p>i made em a picture so you could see it exactly.</p>
<p>edit:
NVM on the second one. i just figured it out.i didnt realize the parentheses was the x part of the triangle equation thing.</p>
<p>Problem #1
The least possible value of y would be equal to x since x<y.
Do this with the equation.
(x+y)(x+y)-(x-y)(x-y)
x^2+2xy+y^2 - (x^2-2xy+y^2)
This gives you 4xy>25
xy>25/4
y=5/2, since if x=y, (5/2)(5/2)=25/4</p>
<p>for the first use difference of squares</p>
<p>2x * 2y >/= 25</p>
<p>4xy = 25</p>
<p>x = y so that y is smallest possible
y= sqrt(25/4)</p>
<p>Problem 2</p>
<p>x=3, y=1</p>
<p>9+3+1=13</p>
<p>so then x=13, y=1</p>
<p>13^2 + 13 + 1 = 183</p>
<p>thanks guys. yeah i didnt realize that y could be the same as x.</p>
