<p>Someone take the integral of:</p>
<p>sin^5(3x)cos3xdx. It's in my homework and I'm exhausted.</p>
<p>u=sin3x
du=3cos3x
(1/3)u^5
u^6/18
sin(3x)^6 / 18</p>
<p>hey, Godfather, here's some hint.</p>
<p>Try to let u = sin 3x
and du = 3 cos 3x dx</p>
<p>That's what I got the first time. Sorry, I have low self esteem I guess. I don't have as high a GPA as any of you, and I haven't taken more than 20 APs, so I guess I just thought I'd get some help here but I don't need any dangit!</p>
<p>Thanks for confirming it though.</p>