help!

<p>I really need to solve this trig problem. I know it's probably really easy, and I'm usually able to get problems like this but for some reason I'm completely blanking out on this one.
it's a really basic right triangles question.</p>

<p>"Two buildings are located 412m apart. The angle of declination between the two is 11.5 degrees. If the taller buildings height is 315m, what is the heigh of the shorter building?</p>

<p>I know I double posted this, but I really need help!</p>

<p>So you have your base of the triangle at 412m and the lower angle (the other bottom angle is the 90<em>) at 11.5. tan(theta)=O/A, tan(11.5)=O/412....
O=tan(11.5)</em>412
O=83.8ish</p>

<p>the O is just how much bigger the taller building is than the smaller building, so 315-O = 231.2ish = size of the smaller building.</p>

<p>That's my guess anyway.</p>