How do I do this LOG problem?

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1

<p>Luckily the last thing we did in PreCal class this year was LOGS. It's still kind of confusing though. </p>

<p>The # in parentheses will be the base(the smaller #)</p>

<p>Log(2)24-Log(2)3=Log(5)x</p>

<p>3
21
72
125
243</p>

<p>I know enough to do Log(2)24/3, which is equal to Log(2)8=Log(5)x. So 2 raised to the 3 equals 8. So Log(5)x=3? Is this saying that 5^3=x, so x=125? Is that right, or did I get tricked by something in the problem?</p>

2

<p>yeah you did it exactly how you should do that problem. The only other way is to convert everything into base 10 and solve it on your calculator.</p>

3

<p>How would you do that? I remember converting to base 10, maybe, but remember how to do it.</p>

4

<p>In your calculator, plug in log 24/log 2 - log 3/log 2 = 3</p>

<p>then you have log (5) x</p>

<p>so, 5 to 3rd power = 125</p>

5

<p>The best way to do this is to recognize that log(2)(24/3) is equal to 3 because 2^3=8 (24/3). So now you have 3=log(5)x. All you need to do now is 5^3=x=125</p>