<p>I know that sounds so wrong! Answer this math question please. It's from the 2010 May QAS.</p>
<p>In the figure above (figure is in the link), BD = 3, DA=6, BC = 12, and DE is parallel to AC. What is the length of EC?</p>
<p>SATquestion.png</a> picture by moneyhermit - Photobucket</p>
<p>Here is the another question.</p>
<p>If x>0, n is a nonnegative integer, and 2x^(n+1) + X^(n+2)= x^(n+3)</p>
<p>What does X^3 equal?</p>
<p>That’s a pretty impressive triangle you have there.</p>
<p>In that one triangle are actually two similar triangles (DBE and ABC; if you don’t understand why, I’ll explain). Now you have a proportion of 3 to 3+6 = 12 to x, or whatever way you want to set it up. X = 36 = BC. 36 - 12 = 24 = EC.</p>
<p>Does the second one have choices or is it a bubble-in one?</p>
<p>second one has answers, both are multiple choice</p>
<p>I’m confused still for the first question. You said 3 to “3+6 = 12 to x”
doesn’t 3+6= 9? I’m very confused. Maybe you can draw a picture? :)</p>
<p>Yeah, 3 + 6 = 9. I thought it would be less confusing that way. D: (3(BD) + 6(DA), or 9, is the length of BA. So it’s BD to BA = BE to BC.)</p>
<p>Could you give the choices for the second one?</p>
<p>Here are the choices for the second one. </p>
<p>A 2+2x+X^2
B 2x+ X^2
C 2+X^2
D2+x
E 3x</p>
<p>Oh yeah, forgot to mention, the answer to the first question is 8. :)</p>
<p>Oh wow, my bad. I thought 12 was BE, not BC. So then it’s 3 to 9 = x to 12. X = 4 = BE. 12 - 4 = 8.</p>
<p>Okay, I’ll let someone else help you with the next one since I’m not good at explaining and I make mistakes. Sorry. D:</p>
<p>Haha, I had solved it correctly before. Thank you! I understand now. The second one is still a mystery!</p>
<p>so for the second question:</p>
<p>it can also be expressed as:</p>
<p>2(x^n)(x) + (X^n)(X^2)=(X^n)(X^3)</p>
<p>This simplifies by dividing all the X^n</p>
<p>= 2x+x^2= X^3</p>
<p>explain the second answer in full detail please :)</p>
<p>you basically have to use the property that</p>
<p>x^(n+1) = (x^n) * (x^1)</p>
<p>Thus,</p>
<p>2x^(n+1) + x^(n+2) = x^(n+3)</p>
<p>can be rewritten as</p>
<p>2(x^n)(x) + (x^n)(x^2) = (x^n)(x^3)</p>
<p>divide both sides by (x^n), isolating x^3</p>
<p>and giving us</p>
<p>2x+x^2</p>
<p>So there is a very simple trick to this question that you need to know for exponents.
Here is a very simple example of what I did for the second question:</p>
<p>Ex. (4^3)(4^5)= 4^(3+5)=4^(8)</p>
<p>For the question above i just did the reverse:</p>
<p>For example 2x^(n+1) is the same thing as (2x^n)(2^1),</p>
<p>I did that for each part of the problem and isolated X^3.</p>
