<p>well its part of an frq, but i need to find the antiderivitive of</p>
<p>v(t)=(t-4)^4sin(t-4)</p>
<p>thanks a bunch!</p>
<p>well its part of an frq, but i need to find the antiderivitive of</p>
<p>v(t)=(t-4)^4sin(t-4)</p>
<p>thanks a bunch!</p>
<p>are you sure its not a calculator problem? integration by parts would work, but that's a BC topic.</p>
<p>As far as I know, integration by parts is firmly within the AB curriculum. Probably one of the the last thing about integrals you learn, along with the inverse trig functions and the volume of a solid, but its definitely part of AB.</p>
<p>integration by parts is NOT on the AP exam. That is a BC topic.</p>
<p>I have seen a question on a past AP Exam that our teacher gave us for practice that required integrations by parts, and she taught us the method in class. Unlike when she taught us L'Hopitals rule, she did no preface it by stating it was a BC topic that we might find useful. So unless I have been terribly misinformed, integration by parts is part of the AB curriculum.</p>
<p>Sorry jaimeastorga2000 but you've been terribly misinformed. Integration by parts is NOT on the AP Calculus AB exam.</p>
<p>Pages 7 and 10</p>
<p>What the...</p>
<p>Ms. Olwell, you LIED to me! <em>breaks down crying</em></p>
<p>wow lol You guys are crazy. But can someone please help me? Calculator is allowed on this particular problem, but even then, I still don't know what to do...</p>
<p>
[quote]
integration by parts would work
[/quote]
</p>
<p>What would you set as u and dv?</p>
<p>Integration by parts USED TO BE an AB topic, which is why some of the older exams had it on there. Some teachers don't know that it's not an AB topic, and some teachers like pretending that it is so that those problems on the older exams don't get skipped.</p>
<p>The calculator won't help you unless you have more information about either the position function (i.e. the position at time 0 is 7) or know the two times in question.</p>
<p>It's not a function you can integrate by hand within the AB curriculum.</p>
<p>If you must know, the answer is</p>
<p>-((x-4)^4 - 12(x-4)^2 + 24)cos(4-x) - 4((x-4)^2 - 6)(x-4)sin(4-x) + C</p>
<p>i dont get whether it's (t-4)^4 * sin(t-4) or (t-4)^(4sin(t-4))</p>
<p>It has to be the first one. The latter has no explicit antiderivative, and even if it did, there's no technique in AP Calculus to find it.</p>
<p>ya. i would use an 89 to find out the answer. This shouldn't be an AB topic.</p>
<p>just put in into an 89 or an TI-Nspire: int(((x-4)^4)*sin(x-4),x)</p>
<p>then just put a + C (for the constant) at the end.</p>