<p>How to integrate, integral (2x^2-x+4)/(x^3+4x), I tried partial fractions and got two variables with the same value?</p>
<p>Have you tried Wolfram Alpha? I don’t know if it will help - it’s been too long since I’ve had to integrate anything!</p>
<p><a href=“integrate (2x^2-x+4)/(x^3+4x) - Wolfram|Alpha”>integrate (2x^2-x+4)/(x^3+4x) - Wolfram|Alpha;
<p>After you plug in the variables, you’ll need to split the integral - at which point it’ll be easy to see.</p>
<p>Pretty straight forward partial fraction problem.
Setup should look like this:</p>
<p>(2x^2-x+4)/[(x)(x^2+4)] = A/x + (Bx+C)/(x^2+4)</p>
<p>Should get A = 1, B = 1, C = -1.</p>
<p>Leads to 1/x + x/(x^2+4) - 1/(x^2+4)</p>
<p>Only part that’s a little tricky is recognizing the arctan derivative in there.</p>