June SAT II Chemistry Thread

<p>Guys, Ionic bonds are IN GENERAL stronger than covalent bonds. This is because of the electrostatic force that occurs when you pull apart an HF molecule. The F- ion and H+ ion that would result are immediately attracted to each other again thanks to the electrostatic force. Again, this is a general statement. </p>

<p>INTRAmolecular force hierarchy:</p>

<p>Ionic>Covalent/Metallic bonds*</p>

<p>*Metallic bonds vary greatly in their strengths, and it’s hard to generalize in relation to covalent bonds. </p>

<p>INTERmolecular force hierarchy:</p>

<p>Ionic>Hydrogen bonding(type of dipole-dipole)>Dipole-Dipole>London dispersion forces</p>

<p>Crystal structure hierarchy (of strength):</p>

<p>Ionic and Covalent-network crystals are the strongest, while metallic crystals vary greatly, and molecular crystals are fairly weak</p>

<p>EDIT: nevermind that was dumb…</p>

<p>but can anyone answer this one?</p>

<p>An experimenter wishes to use test paper to find the pH of a solution. Which of the following is part of the proper procedure for this process?
a. dipping the test paper in the solution while stirring
b. dipping the test paper in the solution without stirring
c. pouring some of the solutions onto the dry test paper
d. dipping the test paper in distilled water and slowly adding the solution to the water while stirring
e. dipping the test paper in distilled water and slowly adding the solution to the water without stirring</p>

<p>just wondering… if i got a 670 on mcgraw hill… does anyone know what im supposed to get?.. -ish</p>

<p>Help please :(</p>

<p>An experimenter wishes to use test paper to find the pH of a solution. Which of the following is part of the proper procedure for this process?
a. dipping the test paper in the solution while stirring
b. dipping the test paper in the solution without stirring
c. pouring some of the solutions onto the dry test paper
d. dipping the test paper in distilled water and slowly adding the solution to the water while stirring
e. dipping the test paper in distilled water and slowly adding the solution to the water without stirring</p>

<p>@vbpointer42- I would say b, because if you stir it, then the paper might read some of the hydroium/hydroxide ions instead of the pH solution as a whole… but I’m not sure of the answer.</p>

<p>my teacher gave me an answer key and it said c. <em>**??? I did not read the answer incorrectly!!! </em> :(</p>

<p>[pH</a> - Acids and Bases](<a href=“http://education.llnl.gov/bep/science/9/tph.html]pH”>http://education.llnl.gov/bep/science/9/tph.html)
I think the procedure is to place it IN the solution.</p>

<p>Does anyone know the approximate curve for this test? How much can you miss to get an 800, 750, and 700?</p>

<p>About -6 for an 800 and probably like -12 for 750 or so.</p>

<p>i believe it is either d/e. cause ur paper won’t be wet or anything to absorb the paper(probably am wrong).</p>

<p>@decillion: 12 questions wrong? for a 750?</p>

<p>Yeah about -11/12 questions.</p>

<p>Hi,
Does anyone have a SAT Chem practise test? There are only 4 in the barron’s book :(</p>

<p>750 on second practice exam</p>

<p>Yeah I’m done for tonight =_=</p>

<p>Yeah I’m reviewing my mistakes and doing Khan Academy like crazy… I guess I’m just not getting it. :/</p>

<p>I really don’t understand this question, nor Barron’s explanation of it…</p>

<p>How many grams of H2SO4 are in 1,000 grams of a 10.% solution? (1 mol of H2SO4 = 98 g)</p>

<p>What’s the answer - 100g H2SO4?</p>

<p>^ Yeah it is… but I don’t understand why they would give you the amus? Does it matter what molecule it is?</p>

<p>amus? Atomic Mass Units? or do you mean this:(1 mol of H2SO4 = 98 g) </p>

<p>If the latter, I don’t know as well. I just did 10% x 1000g to figure out how many grams there was.</p>

<p>Well they gave the g/mol and I just call those amus since they’re technically amus. :)</p>

<p>Yeah… that’s what threw me off. :/</p>

<p>I’m guessing they gave you the the MW of H2SO4 to throw you off. I think anyone who knows simple math would know how to do this problem… though I agree with you - I don’t see why they’d give that to you other than to be a distractor.</p>