<p>"12) X^2<X^3<X.......this may or may not have been it, but i know the answer was "C" "</p>
<p>That can't be correct... what if x were .5? Or did I misread the question, and x must be an integer...?</p>
<p>i think the math experimental was the one with workout equiptment, was that the one which also had the last question with where y=2.5, sumtin wher eu get it downs it 4xy<25</p>
<p>No, that was on the real test. I had a verbal exprimental section, and i had that question.</p>
<p>islanders the workout was experimental (i did not have it)
The 4xy<25 was not.</p>
<p>Ticklemepink: If x=.5
.25<.125<.5
That equation is wrong. Therefore that is the answer.</p>
<p>Oh no! grr! I read it wrong, and I even double checked it! Man, that is so annoying. Oh well, nothing I can do now.</p>
<p>Actually, the question said which of these are not possible, which means that some of the answers are only possible for some number x, not all numbers x. Therefore, plugging in numbers will not work. There is an answer choice that does not work for all x. The rest works for some x, but not all x.</p>
<p>dualityim, you do not plug in the same X for each choice, but different Xs that make it true. I believe the other 4 x's were:
0<x<1, 1<X, X<-1, -1<X<0</p>
<p>Here is another problem, that was unlisted:
If a <b, then which of the following is true?
Answer was a-b<0. The less than sign may have been reversed but the answers is still the same.</p>
<p>ashernm, I agree, but you were sort of confused in your previous response. For all the incorrect choices, you can plug in some value for x and it would work, if you plugged in the right value. But in your response, you plugged it into the correct choice (which works for no values of x), and it didn't work, so you said that was the answer ipso facto. But that is not how you can tell that that choice is incorrect. You will either have to plug in values from a variety of ranges, or use intuitive abilities to figure it out.</p>
<p>duality, using the 4 x values i provided, you do not have to plug them in per se, but understand multiplication of numbers where l number l<1 and numbers greater than 1.</p>
<p>Has the cube problem been resolved? I'm still not convinced that the answer is 24 and not 12 . . . I drew it all out and decided that since the question asked about how many right angles are formed by the EDGES of a cube, the answer is 12, and 24 would be double-counting.</p>
<p>remember, it's formed BY the edges, not AT the edges. Edges are essentially line segments. BY the edges means the angles formed where the line segments meet, i.e. the vertices. There are eight vertices with three angles each, hence the answer 24.</p>
<p>does anyone know for sure if that math section with the pails was experimental? Thanks! (also, if you remember, what else was in that section?)</p>
<p>The math section with the pails is not experimental. I don't remember what else is in that section.</p>
<p>Yeah, I had the pails question, and I had an extra CR section. Dualityim, do you think there's any chance they might throw out the cube question?</p>
<p>so does anyone actually know what the experimental sections were?</p>
<p>I think there is a big chance they might throw out the cube question. However, to be sure, I'll have to know the exact wording. If it's pretty obvious that they asked for the angles formed by the line of the cube (aka the edges), then it probably won't be thrown out after all.</p>
<p>They asked for the number of angles formed by the EDGES of the cube.</p>
<p>Ok... really... I don't see how it could not be 24 (So whoever put 12? or 36? or whatever, explain to me (and like alot more people)) cause there could be two ways of doing it:</p>
<p>1) There are 8 corners to a cube, and there are three right angles at each corner so 8*3 = 24...</p>
<p>2) On each face, there are 4 right angles. A cube has 6 faces. 6*4=24...</p>
<p>OH... I see, some people are talking about the edges... hm... I think that that would be counted in the calculations above... or else there would be like an infinite amount of right angles... I'm excited to hear what people have to say about this...</p>
<p>:)</p>
<p>can anyone explain why the majority say that the answer to the average of x and y was t?</p>
<p>x is the average of t+2 and t. y is the average of t-1 and t[im not sure anymore -_-]</p>