<p>No because everything else would be a radical (under a square root). There are only ten square roots that are rational (no square root) when simplified.</p>
<p>OH I see. Darnit. I actually put 10/100 and then changed it 5 minutes prior to time being called. Thanks for helping me understand the questions</p>
<p>Hopefully 32/33. I’ll be really happy with a 34 :)</p>
<p>Did anyone get the one with" the square root (c^2)
Which one would work?
There’s answer like
-1
-2
3
Pie
and something else
They all works for me…</p>
<p>It was like -3/5 or something. I just tried them all and that one worked.</p>
<p>How was the question worded?</p>
<p>The question was something like this:
“What integer value (c) satisfies the expression √(cˆ2)”</p>
<p>the answer for that is 3 because it asked for an integer and it did not specifically ask for negative solutions (when there is no ± sign in front of the radical it only wants positives)
Further Explanation:</p>
<p>√(-1ˆ2)=1 —(-1) could be a possible answer IF the question would have been ±√(-1^2)</p>
<p>√(-2ˆ2)=2 —(-2) could be a possible answer IF the question would have been ±√(-2^2)</p>
<p>√(3ˆ2)=3 —(3) works</p>
<p>√(∏ˆ2)=∏ —(∏) would work but the question asked for an integer (∏ is irrational)</p>
<p>√(.5ˆ2)=.5 —(.5) is not an integer so it does not work.</p>
<p>agree with vcooper</p>
<p>was there a 20/100 option for the 1-100 problem? if not i probably put 10/100</p>
<p>cus u get sqrt1, sqrt4, sqrt9, sqrt16…and so on…</p>
<p>but for each square root u get a positive and a negative value… and since both positive and negative integers are rational… shouldnt it be 20/100?</p>
<p>36 baby on math
It was easy that the curve is going be horrible</p>
<p>anyone have the exact wording for the 1-100 question</p>
<p>jkaufman: you are referring to a different question which was…
“For what value (a) is 16ˆa=1/(64ˆ(a+1))”</p>
<p>-3/5 is correct</p>
<p>16ˆ(-3/5) ≈ .1895
1/(64ˆ(-3/5+1)) ≈ .1895</p>
<p>oh what about the question for which value of a do you get infinite solutions or something and what did you guys get for the math question…with layers of cans…5 across 4 down…and each layer is one more can than previous or something…i didn’t gt what the question was asking for so i just put c which was 116 or 114 or something like that.</p>
<p>1-100 question:
“the pattern is √1, √2, √3, … √100. What is the ratio of rational numbers to total terms in this sequence?”
-that is basically what the question was asking</p>
<p>Answer: 10/100
Explanation: rational numbers are numbers that can be expressed as a fraction, such as 1/2 or 10/1. A square root of a number that is not a perfect square (perfect squares are the squares of integers, such as 3ˆ2=9, 9 is a perfect square) is always irrational, such as √5≈2.236067977… that decimal cannot be described as a fraction</p>
<p>To figure out the amount of rational numbers we can identify all the perfect squares from 1-100. These are: 1,4,9,16,25,36,49,64,81,100. There are 10 perfect squares from 1-100, and perfect squares are the only rational square roots. Therefore the ratio of rational numbers to total numbers in the sequence is:
10/100</p>
<p>^ yea that was easy</p>
<p>so how about the question with the cans…lol i totally guessed for that one</p>
<p>Infinite solutions question:
“What value (a) makes the system have infinite solutions?
2x+3y=6
4x+6y=3a”</p>
<p>Answer: 4
Explanation: To have infinite solutions, the graphs of the equations must be the same (they will be on top of one another).
The left side of the 2nd equation is directly proportional to the right side by factor 2. To maintain this proportion and satisfy the infinite solutions the right side must also scale up by a factor of 2.
6<em>2=12 therefore the right side of the second equation must equal 12
3</em>a=12 so a=4
this gives us 2x+3y=6 and 4x+6y=12.
Simplified to slope-intercept form, both equations come out to be y=-2/3x+2</p>
<p>The value a=4 makes the graphs of the equations be the same line, yielding infinite solutions.</p>
<p>Any chance a -3 = 33?</p>
<p>@mike
Definitely</p>
<p>^^For the trapezoid, the top length was 4, the bottom was 14, and the height was 12. There was a line dividing it perfectly down the middle, so one half of the trapezoid had a height of 12, a base of 7, and a top segment of 2. Subtract that 2 from the top and 7, and you get a base of 5. 5 and 12 are a pythagorean triple (so 5, 12, and 13), and 13 + 13 + 4 + 12 = 44 for the perimeter.</p>
<p>EDIT: I posted this so late without refreshing the page. It’s already been answered… lol…</p>
<p>Re the cans question - go back to page 2 of this thread and it explains why it was 140.</p>