<ol>
<li><p>One positive integer is said to be "tripatible" with another positive integer if the sum is divisible by 3. Which of the following integers is tripatible with 11?
A. 2
B. 3
C. 4
D. 5
E. 6 </p></li>
<li><p>A two-digit number XY, where X and Y are digits, is 3 times the sum of its digits. Which of the following equations could be used to represent the statement above?
A. 3(X) + Y = 10(X) + Y
B. 3(X) + Y = X + Y
C. 3(X + Y) = 10(X + Y)
D. 3(X + Y) = 10(X) + Y
E. 3(X + Y) = (X + Y)</p></li>
<li><p>[Grid-In] In a certain parking lot that contains 200 cars, 50 percent cars are red, 60 percent are four-door cars, and 70 percent have alloy rims. What is the greatest number of cars in the parking lot that could be green two-door cars with alloy rims.</p></li>
<li><p>[Grid-In] If the area of a circle is pi/16, what is the diameter of the circle?</p></li>
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<ol>
<li><p>11+4=15 which is divisible by 3. The answer is C</p></li>
<li><p>Well the second part of the question says 3 times the sum of X and Y which is 3(X+Y). To find the two digit number you need to multiply X by 10 (ex. 2*10 makes it 20) and add Y in the ones place.</p></li>
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<p>So the equation is 3(X+Y)=10X+Y. D</p>
<ol>
<li>Well lets change the percentages to numbers. 100 cars are red (so 100 are not red) 120 cars are four-door cars (thus 80 are not four-door cars). 140 cars have alloy rims. The question is what is the greatest possible number of green, two-door cars with alloy rims. 100 cars can be green, 80 can be two-door cars, and 140 can have alloy rims. You have to take the lowest number of this set since that is the limiting reactant.</li>
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<p>The answer is 80.</p>
<ol>
<li>Area of a circle=pi*radius^2. If you plug in pi/16 for the area then just solve for the radius.</li>
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<p>pi/16=pi*radius^2 - divide by pi (or multiply by 1/pi if that is easier to understand)
1/16=radius^2 - square root of both sides
1/4=radius</p>
<p>Diameter is twice the radius so the answer is 1/2 or 0.5</p>
<p>1) C</p>
<p>11+2 = 13. Not divisible by 3
11+3=14. Not div.
11+4=15. Is div by 3.
11+5=16. Not.</p>
<h2>11+6=17. Not.</h2>
<p>2) Sum of digits = X+Y. 3 Times sum of digits 3X+3Y. Therefore XY=3X+3Y.</p>
<h2>Now XY = 10X + Y. (Say number is 28. Then it’s 2*10+8 = 28) Therefore 3(X+Y)=10X+Y = D</h2>
<p>3) Max cars that can be green = 100. Max cars that can be two-doored = 40% of 200 = 80. Max cars that can have alloy rims = 70% of 200 = 140. The minimum of these is 80, so at most <strong><em>80</em></strong> cars can be all that.</p>
<p>4) pi r^2 = pi/16. r^2 = 1/16. r = 1/4. d = 1/2</p>