<p>Could you please help me answer this question? I read the answer but it isnt helping</p>
<p>Thanks</p>
<p>If A is the sum of integers from 1-50 and B is the sum of integers from 51 to 100. then what is the value of B-A?</p>
<p>51 - 1 + 52 - 2 + 53 - 3 + . . . + 100 - 50 </p>
<p>= 50 + 50 + 50 + … + 50</p>
<p>=50(50)</p>
<p>=2500</p>
<p>thanks, that really helped.</p>
<p>If anyopne has the blue book could they do problem 19 on page 523?</p>
<p>I keep getting it wrong!! Thanks :)</p>
<p>Wowie //</p>
<p>The triangle is equilateral, so all sides are 2.
The diameter is a perpendicular bisector, because it makes a right angle.</p>
<p>So you can assume that WZ is 1
And using the 30:60:90 rule, you can assume that WY is √3
Now, you just use A=πr^2</p>
<p>A = πr^2
= π(√3/2)^2
= 3π/4</p>