<p>3,5,-5,...</p>
<p>The first term in the sequence of numbers above is 3. Each even-numbered term is 2 more than the previous term, and each odd-numbered term (after the first) is -1 times the previous term. Ex: the 2nd term is 3+2, and the 3rd term is (-1) times 5. What is the 55th term in this sequence?</p>
<p>a) -5
b) -3
c) -1
d) 3
e) 5</p>
<p>The answer is a(-5), but every time I try this problem I come up with 3. Any help?</p>
<p>umm, this is in the consolidated book of BB math problems stickied above, but here's the solution anyways you bum.</p>
<p>Write out the terms and you should get
3, 5, -5, -3, 3, 5, -5, -3,</p>
<p>Notice that the pattern repeats itself every 4 terms.
How many times does 4 go into 55? 13 times with a remainder of 3
what's the third term? The Answer -5.</p>
<p>^ditto
Don't forget to look for solutions in
<a href="http://talk.collegeconfidential.com/sat-preparation/339734-consolidated-list-blue-book-math-solutions-3rd-ed.html%5B/url%5D">http://talk.collegeconfidential.com/sat-preparation/339734-consolidated-list-blue-book-math-solutions-3rd-ed.html</a></p>
<p>wow, you guys have just ushered me into a whole new level of mathematical experience.</p>
<p>Thanks</p>
<h1>Enjoy!</h1>